Assume that X — N(8, 4). What is the probability that Xwill assume a value between X1 = 4 and X2 = 12? To compute the required probability, we compute the Zvalues as
Now from Table D.1 we observe that Pr(0 < Z < 2) = 0.4772. Then, by symmetry, we have Pr(-2 < Z < 0) = 0.4772. Therefore, the required probability is 0.4772 + 0.4772 = 0.9544. (See Figure A.4.)
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