Consider the experiment of throwing a die numbered 1 through 6. The sample space consists of the outcomes 1, 2, 3, 4, 5, and 6. These six events therefore exhaust the entire sample space. The probability of any one of these numbers showing up is 1/6 since there are six equally likely outcomes and any one of them has an equal chance of showing up. Since 1, 2, 3, 4, 5, and 6 form an exhaustive set of events, P(1 + 2 + 3 + 4 + 5 + 6) = 1 where 1,2,3,... means the probability of number 1 or number 2 or number 3, etc. And since
1,2 6 are mutually exclusive events in that two numbers cannot occur simultaneously,
P(1 + 2 + 3 + 4 + 5 + 6) = P(1) + P(2) + •••+ P(6) = 1.
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