Let us return to Example 3.2 about food expenditure in India. Using the data given in (3.7.2) and adopting the format of (5.11.1), we obtain the following expenditure equation:
FoodExp, = 94.2087 + 0.4368 TotalExp, se = (50.8563) t = (1.8524) p = (0.0695) r2 = 0.3698; Fi,53 = 31.1034
were true, what is the probability of obtaining a value of 0.4368? Under the null hypothesis, we observe from (5.12.2) that the t value is 5.5770 and the p value of obtaining such a t value is practically zero. In other words, we can reject the null hypothesis resoundingly. But suppose the null hypothesis were that fS2 = 0.5. Now what? Using the t test we obtain:
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